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Grade: Upto college level


A heavy smooth chain of mass 'm' / length and total length 'L' hanging from smooth table edge. The length of chain on table is 'x''. The height of table top from ground is 'H'. If the motion starts from rest (t=0.0 sec) at what time the entire chain will descend on the ground.

10 years ago

Answers : (1)

Askiitians Expert Bharath-IITD
23 Points
							Dear Bhaskar,

We know the equation of motion as S = u + (1/2)a* t^2

Now the center of mass of the hanging part is at its midpiont and hence it is at height of 
H-[(L-x)/2] from the ground.

u(initial velocity)=0
a= g   (acceleration due to gravity) , S=H-[(L-x)/2]
Thus we would get time t= squareroot of{[(2*H)-(L-x)]/g}  seconds
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Askiitians Experts
Adapa Bharath
10 years ago
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