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When two bodies of masses m and M respectively are connected by a light string. masses m & M are moving with velocities v & u in opposite direction respectively. maximum compression of spring is
Dear Arshad, As the masses m and M connected by a light spring are moving towards each other, the spring keeps on compressing as long as they move towards each other. Hence the compression keeps on increasing as long as the masses move towards each other. This means that, when the two masses come to rest the spring no longer undergoes any further compression hence it reached its maximum compression when both the masses come to rest. using conservation of energy, ( as there isn't any non conservative force ), initially the energy of the masses plus spring system is, E initial = 1/2 mv² + 1/2Mu² Finally the Kinetic energies are zero and they are converted to spring potential energy E final = 1/2 kXmax2 where Xmax is the maximum compression in the spring E initial = E final from conservation of energy from this equation we can find maximum compression of the spring, if variables m,M,v,u and k are given. Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best arshad !!!Regards,Askiitians ExpertsRohith Gandhi
Dear Arshad,
As the masses m and M connected by a light spring are moving towards each other, the spring keeps on compressing as long as they move towards each other. Hence the compression keeps on increasing as long as the masses move towards each other.
This means that, when the two masses come to rest the spring no longer undergoes any further compression hence it reached its maximum compression when both the masses come to rest.
using conservation of energy, ( as there isn't any non conservative force ), initially the energy of the masses plus spring system is,
E initial = 1/2 mv² + 1/2Mu²
Finally the Kinetic energies are zero and they are converted to spring potential energy
E final = 1/2 kXmax2 where Xmax is the maximum compression in the spring
E initial = E final from conservation of energy
from this equation we can find maximum compression of the spring, if variables m,M,v,u and k are given.
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best arshad !!!Regards,Askiitians ExpertsRohith Gandhi
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