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As shown in the figure, a smooth rod is mounted just above a table top. A 10 kg collar, which is able to slide on the rod with negligible friction is fastened to a spring whose other end is attatched to a pivot at O. The spring has negligible mass, a relaxed length of 10 cm and a spring constant of 500 N/m. The collar is released frm rest at point A. Here, in the figure, BC = 20 cm, AB = 40 cm, and B0 = 30 cm.
What is it's velocity as it passes point B and C.???
Here is the diagram
Dear Sanchit
Calculate the length AO =50 CM
spring natural lenghth is given 10 cm
so springh is stretched by 50-10 = 40 cm
Total energy at point A=(1/2)*500*(.40)2
=40 Nm
At point B Spring Stretched by =30-10 =20 cm
Total energy at point B=(1/2)*500*(.20)2+(1/2)*10*v2
=10 +5v2
At point C Spring Stretched by =26 cm
Total energy at point C=(1/2)*500*(.26)2+(1/2)*10*v2
Now first equate energy at A and B and find the velocity at B
Similarly equate energy at A and c and find the velocity at c
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