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A body of mass 1 kg thrown upwards with a velocity of 10 m/s comes to rest (momentarily) after moving 4m? what is the work done by the air drag in the process
Dear Raghava,
m=mass=1kg, mv2/2=mgh+ work done by air drag
work done by air drag=1*(50-4g)=50-40=10Joule
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CHETAN MANDAYAM NAYAKAR
potential energy=mgh==1*10*4=40
kinetic energy=1/2*m*v2 =50
work done by the air drag= sum of kinetic and potential energy=50+40=90Nm.
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