an observer and a vehicle both start moving together from rest with acc 5 m/s^2 and 2 m/s^2 in same directions .there is a 2 kg block on the floor of the vehicle and coeff of friction is 0.3 betwwen their surfaces . find the work done by the frictional force on the block as observed by the running observer during first 2 secinds of motion ?

Pls reply soon

thnx

Question

an observer and a vehicle both start moving together from rest with acc 5 m/s^2 and 2 m/s^2 in same directions .there is a 2 kg block on the floor of the vehicle and coeff of friction is 0.3 betwwen their surfaces . find the work done by the frictional force on the block as observed by the running observer during first 2 secinds of motion ?

Pls reply soon

thnx

Chetan Mandayam Nayakar · Answer

limiting friction=kmg=2*10*0.3=6N, inertial force=2*2=4N, so there is no slipping. Force of friction on block=4N, distance travelled during first two seconds of motion=(1/2)*3*4=6m, therefore work done=6m*4N =24 Joule

Swamynathanvp · Answer

f max = 0.3×2×10 a of block wrt ground is 2m/s 2 which is provided by f = ma=2×2=4N Relative a = 2-5= -3m/s 2 Displacement=1/2at 2 = 1/2×-3×2×2=-6m Work done = f.s = 4 ×-6=-24J

relkjew · Answer

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