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the velocity of a particle moving in positive direction of x-axis is varies as v= root 5 x . assuming that at t=0 , particle was at x=0 . what is acceleration of the particle.?

the velocity of a particle moving in positive direction of x-axis is varies as v= root 5 x . assuming that at t=0 , particle was at x=0 . what is acceleration of the particle.?


 

Grade:11

2 Answers

Tushar Makkar
37 Points
9 years ago

hi swati,

a=dv/dt;

a=(dv*dx)/(dx*dt);multiplying and dividing dx;

a=v*dv/dx;(dx/dt=v)---1

v=root(5x)

dv/dx=d(root 5x)/dx;

dv/dx=root(5)/(2*root(x));

putting in 1;

value of v and dv/dx

root x gets cancelled 

so a= 5/2;

 

pls. approve the ans. if u understood the concept

rakesh kumar
18 Points
9 years ago

v=root5x

so,v square =5x

also since u=0

so v square=2ax

5x= 2ax

so

a-2.5

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