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the velocity of a particle moving in positive direction of x-axis is varies as v= root 5 x . assuming that at t=0 , particle was at x=0 . what is acceleration of the particle.?
hi swati,
a=dv/dt;
a=(dv*dx)/(dx*dt);multiplying and dividing dx;
a=v*dv/dx;(dx/dt=v)---1
v=root(5x)
dv/dx=d(root 5x)/dx;
dv/dx=root(5)/(2*root(x));
putting in 1;
value of v and dv/dx
root x gets cancelled
so a= 5/2;
pls. approve the ans. if u understood the concept
v=root5x
so,v square =5x
also since u=0
so v square=2ax
5x= 2ax
so
a-2.5
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