badge image

Enroll For Free Now & Improve Your Performance.

User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 12


In the arrangement shown, the apppreciable friction exisits only b/w the bodym and the wedge.The frictional coeff being equals to @. The masses of pulley and the thread are negligible. Show that the acc of body m w.r.t the horizontal surface on which the wedge slides is given by mg / [2m+@m+M]

11 years ago

Answers : (1)

Pratham Ashish
17 Points


fbd of m

fbd of M

let the acceleration of m in horizontal direction be  a, then from fbd.

        N = ma..............................(1)

the acce. of the M will also be a,

so,     T - N = Ma

     T- ma = Ma .....................................(2)

from the constraint of the length of the cord,

    the vertical accel. of  m  will be the same as horizontal one,

balancing the vertical forces on m ,

    mg -T - @ma = ma

   mg -T -ma (@+1)  =0 ......................................(3)

putting T = Ma +ma   from eq. (2)   to (3)    we get,

    mg - (M+m)a - ma (@+1) = 0

     (2m+ M + @m) a = mg

     a = mg /(2m+ M + @m)


11 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details