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A cylinder of mass M and radius R is resting on a horizontal platform(which is parallel to the x-y plane)with its axis fixed along the y axis and free to rotate about its axis. The platform is given a motion in the x direction given by x=A cos(ωt).there is no slipping between the cylinder and the platform.The max torque acting on the cylinder during its motion is?

debadutta mishra , 15 Years ago
Grade 11
anser 2 Answers
Chetan Mandayam Nayakar

Dear Debadutta,

acceleration a=d2x/dt2=-w2Acos(wt),lamaxl=w2A,

maximum angular acceleration=w2A/R

Torque=Iα=(MR2/2)(w2A/R)=(MRAw2/2)

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CHETAN MANDAYAM NAYAKAR

Last Activity: 14 Years ago
Ashwin Muralidharan IIT Madras

Hi Debadutta,

 

The max acn of the platform would be:

2.

 

So max Torque, ζmax = A(MRω2)/2.

 

Best Regards,

Ashwin (IIT Madras).

Last Activity: 14 Years ago
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