A block of mass 5 Kg is suspended from the end of a vertical spring which is stretched by 10cm under the load of the block. the block is given a sharp impulse from below so that it acquires an upward speed of 2m/s . How high will it rise?.........i

actually i saw the following equation in the solution

1/2kx² + 1/2mv² = ½(h – x)² + mgh

i didn't understand how (h-x) can be written....................PLZ EXPLAIN

Dear pooja

See the pic for the solution

All the best.

AKASH GOYAL

AskiitiansExpert-IITD

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