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A block of mass 5 Kg is suspended from the end of a vertical spring which is stretched by 10cm under the load of the block. the block is given a sharp impulse from below so that it acquires an upward speed of 2m/s . How high will it rise?.........i
actually i saw the following equation in the solution
1/2kx2 + 1/2mv2 = ½(h – x)2 + mgh
i didn't understand how (h-x) can be written....................PLZ EXPLAIN
Dear pooja
See the pic for the solution
All the best.
AKASH GOYAL
AskiitiansExpert-IITD
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