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A block of mass 5 Kg is suspended from the end of a vertical spring which is stretched by 10cm under the load of the block. the block is given a sharp impulse from below so that it acquires an upward speed of 2m/s . How high will it rise?.........i

actually i saw the following equation in the solution

1/2kx2 + 1/2mv2 = ½(h – x)2 + mgh

i didn't understand how (h-x) can be written....................PLZ EXPLAIN

Pooja singh , 14 Years ago
Grade 11
anser 1 Answers
AKASH GOYAL AskiitiansExpert-IITD

Last Activity: 14 Years ago

Dear pooja

See the pic for the solution

All the best.

AKASH GOYAL

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