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A bullet of mass 1g shot vertically up by a gun gives a force 2N for 0.001s.Calculate the maximum height attained by a bullet. Neglect air friction and take g=10ms-2. Solve this problem…………..
force = change in momentam/time 2 = mv-mu/t u=0 so v=2m/s we have v2=u2+2as final velocity when particle reaches highest point is 0 so 0 =u2-2gHmax Hmax = u2/2g=4/20=0.2m ans
force = change in momentam/time
2 = mv-mu/t
u=0 so
v=2m/s
we have v2=u2+2as
final velocity when particle reaches highest point is 0
so 0 =u2-2gHmax
Hmax = u2/2g=4/20=0.2m ans
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