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Q.10 A seamless tube 3 cm out side diameter is reduced in length on a lathe with the help of a single point cutting tool. The cutting speed is 40 m per min. the depth of cut is 0.125 mm. The length of continuous chip, for one revolution of the tube, as measurement comes to be 17.77cm. The cutting force is 200 kg and the feed force is 75 kg. The rake angle of the tool is 35°. Calculate : (i) Coefficient of friction (ii) Chip thickness ratio (iii) Shear plane angle (iv) Velocity of the chip along the tool face. (v) Velocity of shear along shear plane.

yuvaraj.R yuva , 15 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To solve the problem you've presented, we need to break it down into several parts. We will calculate the coefficient of friction, chip thickness ratio, shear plane angle, velocity of the chip along the tool face, and the velocity of shear along the shear plane using the given parameters. Let's go through each calculation step by step.

Given Data

  • Outside diameter of the tube: 3 cm
  • Cutting speed (V): 40 m/min
  • Depth of cut (d): 0.125 mm = 0.0125 cm
  • Length of continuous chip for one revolution (L): 17.77 cm
  • Cutting force (F_c): 200 kg
  • Feed force (F_f): 75 kg
  • Rake angle (α): 35°

Calculating Coefficient of Friction

The coefficient of friction (µ) can be calculated using the formula:

µ = F_f / F_c

Substituting the values:

µ = 75 kg / 200 kg = 0.375

Determining Chip Thickness Ratio

The chip thickness ratio (r) is given by the formula:

r = t_0 / t

Where:

  • t_0 = depth of cut = 0.0125 cm
  • t = chip thickness

To find the chip thickness (t), we can use the relationship:

t = L / (π * D)

Where D is the diameter of the tube. Since the diameter is 3 cm, we have:

t = 17.77 cm / (π * 3 cm) ≈ 1.88 cm

Now, substituting into the chip thickness ratio formula:

r = 0.0125 cm / 1.88 cm ≈ 0.00664

Calculating Shear Plane Angle

The shear plane angle (φ) can be calculated using the formula:

tan(φ) = (r * cos(α)) / (1 - r * sin(α))

Substituting the values:

tan(φ) = (0.00664 * cos(35°)) / (1 - 0.00664 * sin(35°)

Calculating cos(35°) and sin(35°):

  • cos(35°) ≈ 0.8192
  • sin(35°) ≈ 0.5736

Now substituting these values:

tan(φ) = (0.00664 * 0.8192) / (1 - 0.00664 * 0.5736) ≈ 0.00544

Thus, φ = arctan(0.00544) ≈ 0.312°

Velocity of the Chip Along the Tool Face

The velocity of the chip (V_c) along the tool face can be calculated using the formula:

V_c = V * (1 + r)

Substituting the values:

V_c = 40 m/min * (1 + 0.00664) ≈ 40.2656 m/min

Velocity of Shear Along Shear Plane

The velocity of shear (V_s) can be calculated using the formula:

V_s = V * cos(φ)

Substituting the values:

V_s = 40 m/min * cos(0.312°) ≈ 40 m/min * 0.9998 ≈ 39.992 m/min

Summary of Results

  • Coefficient of Friction (µ): 0.375
  • Chip Thickness Ratio (r): 0.00664
  • Shear Plane Angle (φ): 0.312°
  • Velocity of the Chip Along the Tool Face (V_c): 40.2656 m/min
  • Velocity of Shear Along Shear Plane (V_s): 39.992 m/min

These calculations provide a comprehensive understanding of the machining process for the seamless tube. Each parameter plays a critical role in determining the efficiency and effectiveness of the cutting operation.

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