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A ball of mass 50 kg is moving with a speed of 2m/s strikes a plane surface at an angle of incidence 45 degrees. the ball is reflected by the plane at an equal angle of reflection at the same speed. calculate (a) the magnitude of the change of momentum of the ball . (b)the change in the magnitude of the momentum of the ball
let ball is moving in x-y plane & approaching a wall at an angle45 degree which is placed in y-z plane...
initial momentam of ball is Pi =mvcos45 i + mvsin45(-j)
finally it returnes at same angle & with same velocity so its final momntam is
Pf = mvcos45(-i) + mvsin45(-j)
change in momentam= Pi - Pi =2mvcos45
=21/2 mv
=100.21/2 or 100sqrt2 ans
approve if u like
dear pooja singh ,
initially the ball s trikes theplanem akinganan gleof 45 degrees withthe plane and after the collision the ball makes an angleof45 degrees
then we canconserve momentum in both the directions:
x-direction
(a) magnitude of change in momentum = 50* 21/2
(b) but change in magnitude =0
similarly,
y-direction
(a) magnitude of change in momentum = 0
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