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prove that the path followed by a projectile is a straigt line as seen from another projectile.
eq of path of projectile is s=ucos@ -gt2/2
if two projectiles are projected from horizontal ground with different initial velocity and angle....both these quantities are known then at any time t
coordinates of A, S1=(UacosA)t i - gt2/2 j
coordinates of B, S2=(UbcosB)t i - gt2/2j
coordinates of A wrt to B is S2-S1=t(UacosA-UbcosB)i + 0 j
Xi + Yj = kt i + 0j (UacosA-UbcosB = constant=k)
ie X=kt is a straight line
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