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Assuming that the Truck is moving with constant Power (P), and assuming that F is the resistive force acting on the truck,
P = F x Velocity
P = (η xN) x 10, where η = dynamic friction, N = Normal Reaction = 200 kg xg
P = η x 200g x 10...........(1)
After 50 seconds, the power remaining same,
P = η x 100g x V...........(2), where V is the velocity after 100 Kg of water is unloaded in 50 seconds
Equating (1) and (2), Velocity V = 20 m/s
Dear Visheshh, Assuming that the Truck is moving with constant Power (P), and assuming that F is the resistive force acting on the truck, P = F x Velocity P = (η xN) x 10, where η = dynamic friction, N = Normal Reaction = 200 kg xg P = η x 200g x 10...........(1) After 50 seconds, the power remaining same, P = η x 100g x V...........(2), where V is the velocity after 100 Kg of water is unloaded in 50 seconds Equating (1) and (2), Velocity V = 20 m/s Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Regards Vijay Luxmi
Dear Visheshh,
Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Regards
Vijay Luxmi
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