Assuming that the Truck is moving with constant Power (P), and assuming that F is the resistive force acting on the truck,

P = F x Velocity

P = (η xN) x 10, where η = dynamic friction, N = Normal Reaction = 200 kg xg

P =  η x 200g x 10...........(1)

After 50 seconds, the power remaining same,

P = η x 100g x V...........(2),  where V is the velocity after 100 Kg of water is unloaded in 50 seconds

Equating (1) and (2), Velocity V = 20 m/s

Dear Visheshh,

Assuming that the Truck is moving with constant Power (P), and assuming that F is the resistive force acting on the truck,

P = F x Velocity

P = (η xN) x 10, where η = dynamic friction, N = Normal Reaction = 200 kg xg

P =  η x 200g x 10...........(1)

After 50 seconds, the power remaining same,

P = η x 100g x V...........(2),  where V is the velocity after 100 Kg of water is unloaded in 50 seconds

Equating (1) and (2), Velocity V = 20 m/s

Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Regards