# A truck is moving with a uniform velocity of 10 m/s.A leak occurs in the water tank of the truck at the rate of 2 kg/s.What is the speed of the truck after 50 seconds if the mass of the truck was 100 kg and mass of water in the tank initially was 100 kg?

Piyush Gupta
18 Points
13 years ago

Assuming that the Truck is moving with constant Power (P), and assuming that F is the resistive force acting on the truck,

P = F x Velocity

P = (η xN) x 10, where η = dynamic friction, N = Normal Reaction = 200 kg xg

P =  η x 200g x 10...........(1)

After 50 seconds, the power remaining same,

P = η x 100g x V...........(2),  where V is the velocity after 100 Kg of water is unloaded in 50 seconds

Equating (1) and (2), Velocity V = 20 m/s

357 Points
13 years ago

Dear Visheshh,

Assuming that the Truck is moving with constant Power (P), and assuming that F is the resistive force acting on the truck,

P = F x Velocity

P = (η xN) x 10, where η = dynamic friction, N = Normal Reaction = 200 kg xg

P =  η x 200g x 10...........(1)

After 50 seconds, the power remaining same,

P = η x 100g x V...........(2),  where V is the velocity after 100 Kg of water is unloaded in 50 seconds

Equating (1) and (2), Velocity V = 20 m/s

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