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A 1 m diameter sphere is droped from an evacuated 145 m drop tower.1) how long is sphere in free fall ??2) when it reaches bottom, it experiences an avg decceleration of 25 g . Through wat dist it travel during decceleration ??
Dear Mohit,
s = ut + 1/2 at2 (where a = g)145 = 0 + 1/2 10 t2t = sqrt(29) sSecond question is a bit shady. From average decceleration one can't calculate the distance, only change in velocity. More precisely it should have mentioned "CONSTANT" decceleration. Thenv2 = u2 + 2as will give you the answer where u = at = 10*sqrt(29) and v = 0.Please feel free to post as many doubts on our discussion forum as you can.we will get you the answer and detailed solution very quickly. All the best.Regards,Askiitians Experts,Gokul Joshi
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