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Grade 11,

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the speed of a train increases at a constant rate (alpha) from zero to v and then remains constant for an interval and finally decreses to zero at a constant rate(beta).the total distance travelled by the train is L.the time taken to complete the journey is t.then t is minimum value when v equals to?

the speed of a train increases at a constant rate (alpha) from zero to v and then remains constant for an interval and finally decreses to zero at a constant rate(beta).the total distance travelled by the train is L.the time taken to complete the journey is t.then t is minimum value when v equals to?

Grade:11

4 Answers

Priyansh Goel
21 Points
13 years ago

I feel question is asking for min. value of t, what is value of v?

Then ans is 0. Time will be min when body starts the motion i.e its initial velocity is asked.

 

 

Plz. do point out my error,if any.

 

Plz. approve my answer if it is right.

 

sanskriti singh
16 Points
13 years ago

sorry the answer isnt right.the right answer is root over 2L(ALPHA)(BETA) DIVIDED BY ALPHA+BETA. i need the explaination of the answer

 

 

 

 

 

 

 

KALA CHAND MAITI
13 Points
8 years ago
sorry both of you..but the answer is t=L/v+y/2(1/alpha+1/beta)
Lord of Galaxy
11 Points
8 years ago
Sorry kala Chand Maiti, but you have not understood the question.
He is not asking for the time taken, but the velocity v that corresponds to the least time.

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