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Grade 11Mechanics

the speed of a train increases at a constant rate (alpha) from zero to v and then remains constant for an interval and finally decreses to zero at a constant rate(beta).the total distance travelled by the train is L.the time taken to complete the journey is t.then t is minimum value when v equals to?

Profile image of sanskriti singh
15 Years agoGrade 11
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4 Answers

Profile image of Priyansh  Goel
15 Years ago

I feel question is asking for min. value of t, what is value of v?

Then ans is 0. Time will be min when body starts the motion i.e its initial velocity is asked.

 

 

Plz. do point out my error,if any.

 

Plz. approve my answer if it is right.

 

Profile image of sanskriti singh
15 Years ago

sorry the answer isnt right.the right answer is root over 2L(ALPHA)(BETA) DIVIDED BY ALPHA+BETA. i need the explaination of the answer

 

 

 

 

 

 

 

Profile image of KALA CHAND MAITI
10 Years ago
sorry both of you..but the answer is t=L/v+y/2(1/alpha+1/beta)
Profile image of Lord of Galaxy
10 Years ago
Sorry kala Chand Maiti, but you have not understood the question.
He is not asking for the time taken, but the velocity v that corresponds to the least time.