Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear cathy
E =1/2 Iw12 - 1/2 Iw22
=I/2 [w12 - w22]
300 = I/2 [ w12 - w22]
w1 = 2*∏*600 /60 = 20∏ rad/sec
w2 = 2*∏*540 /60 = 18∏ rad/sec
put the value of w1 and w2 and calculate the value of moment of Inertia
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