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`         1 a flywheel rotating about fix axis  has a kinetic energy of 360 joule when it angular speed 30 Radian per second the moment of inertia of wheel`
10 months ago

Vikas TU
11143 Points
```							Hiii Moment of Inertia = Mr^2omega = 30 radian , and kinetic energy = 360 jouleRotational KE = ½ * I * W^2 ( W = omega)Put the value you will get I = 12/15 = 0.80
```
10 months ago
Khimraj
3008 Points
```							I = mrrmoment of inertia is equal to the product of mass and the square of the radius.we know rotational kinetic energy = 1/2iww.then given w= 30 rad and k.E = 360j k.e= 1/2iww 360 = 1/2× i×30×30i= 360×2÷30×30I=12÷15
```
10 months ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions