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Grade: 11
        
How many grams of Fe2O3 can be formed from the rusting of 446 grams of Fe according to the   reaction: 4Fe + 3O2 → 2Fe2O3 and excess oxygen?
  1. 320 g
  2. 223 g
  3. 159 g
  4. 640 g
4 months ago

Answers : (1)

Shivangi Khatter
askIITians Faculty
447 Points
							dear student
the correct answer is(D)
4 *55.8 grams of Fe gives 2 160 grams of Fe2O3
446 grams of Fe = 2 *160 *446/(4 *55.8) = 640 grams
4 months ago
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