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x√ (1+y) = -y √(1+x)Sqare both sidesx^2(1+y) = (y^2)(1+x)x^2 + y(x^2) = y^2 + x(y^2)
(x-y)(x+y) + xy(x-y) = 0(x-y)(x+y+xy) = 0
x can't be equal to y , thereforex+y+xy = 0y = -x / (1+x)Differentiate eqn w.r.t x
dy/dx = -1/(1+x)^2
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