Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Two short magnets each of moment 10 are placed in end on position so that their centres are 0.1m apart. The force between them is

Two short magnets each of moment 10 are placed in end on position so that their centres are 0.1m apart. The force between them is

Grade:12

2 Answers

Arun
25763 Points
2 years ago
Dear student
 
F = Mu/4pi 6 M1 M2 /d^4
 
hence F = 0.6 N
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
 
Khimraj
3007 Points
2 years ago
 
formula for force BT parallel placed magnet f=Mo/4π(6m1m2/r4)
No=4π×10^-7 therefore f=10^-7(6×10×10/(0.1^4)=0.6N

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free