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Two short magnets each of moment 10 are placed in end on position so that their centres are 0.1m apart. The force between them is

Two short magnets each of moment 10 are placed in end on position so that their centres are 0.1m apart. The force between them is

Grade:12

2 Answers

Arun
25758 Points
3 years ago
Dear student
 
F = Mu/4pi 6 M1 M2 /d^4
 
hence F = 0.6 N
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
 
Khimraj
3007 Points
3 years ago
 
formula for force BT parallel placed magnet f=Mo/4π(6m1m2/r4)
No=4π×10^-7 therefore f=10^-7(6×10×10/(0.1^4)=0.6N

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