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Two paraller long smooth conducting rails separated by a distance l are
connected by a movable conducting connector of mass m. Terminals of the
rails are connected by the resistor R and the capacitor C as shown in
fig. A uniform magnetic field B perpendicular to the plane of the rail
is switched on. The connector is dragged by a constant force F. Find
the speed of the connector as a function of time if the force F is
applied at t = 0. Also find the terminal velocity of the conductor.

Aditi Chauhan , 12 Years ago
Grade 10
anser 1 Answers
Askiitians Tutor Team

To tackle this problem, we need to analyze the motion of the conducting connector within the context of electromagnetic induction and Newton's laws. The setup involves a conducting connector moving between two parallel rails in a magnetic field, which induces an electromotive force (emf) as the connector moves. Let's break this down step by step.

Understanding the System Dynamics

Initially, when the magnetic field B is switched on, and the connector is at rest, there is no induced current. However, once the force F is applied at time t = 0, the connector begins to move, and we can analyze the forces acting on it.

Induced EMF and Current

As the connector moves with a velocity v, it cuts through the magnetic field lines, inducing an emf (ε) given by Faraday's law of electromagnetic induction:

  • ε = B * l * v

Where:

  • B = magnetic field strength
  • l = length of the connector (distance between the rails)
  • v = velocity of the connector

This induced emf causes a current (I) to flow through the circuit, which includes the resistor R and the capacitor C. According to Ohm's law, the current can be expressed as:

  • I = ε / R = (B * l * v) / R

Force on the Connector

The current flowing through the connector in the magnetic field experiences a magnetic force (F_m) given by:

  • F_m = I * B * l = (B * l * v / R) * B * l = (B^2 * l^2 * v) / R

Now, applying Newton's second law to the connector, we have:

  • F - F_m = m * a

Where:

  • F = applied force
  • F_m = magnetic force
  • m = mass of the connector
  • a = acceleration of the connector

Setting Up the Equation of Motion

Substituting the expression for F_m into the equation gives:

  • F - (B^2 * l^2 * v) / R = m * a

Since acceleration (a) is the derivative of velocity (v) with respect to time (t), we can rewrite this as:

  • F - (B^2 * l^2 * v) / R = m * (dv/dt)

Solving the Differential Equation

This is a first-order linear differential equation. Rearranging gives:

  • m * (dv/dt) = F - (B^2 * l^2 * v) / R

To solve this, we can separate variables:

  • dv / (F - (B^2 * l^2 * v) / R) = dt / m

Integrating both sides will yield the velocity as a function of time. The integration will involve some algebraic manipulation, but the general form will lead to an expression for v(t).

Finding Terminal Velocity

The terminal velocity (v_t) occurs when the acceleration becomes zero, meaning the net force acting on the connector is zero:

  • F - (B^2 * l^2 * v_t) / R = 0

Solving for v_t gives:

  • v_t = (F * R) / (B^2 * l^2)

Summary of Results

In summary, the speed of the connector as a function of time can be derived from the integration of the differential equation, while the terminal velocity can be calculated directly from the balance of forces. This analysis shows how electromagnetic principles govern the motion of the connector in the magnetic field.

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