1800-150-456-789
FlagBACK
Flag Magnetism> two parallel coaxial circular coils of eq...
question mark

two parallel coaxial circular coils of equal radius R and equal no of turns N carry equal currents I in the same direction and are represented by a distance 2R. find the magnitude and direction of the net magnetic field produced at the mid-point of the line joining their centres.

Rahul Premchand , 8 Years ago
Grade 12
anser 2 Answers
Vikas TU

Last Activity: 8 Years ago

. Radius of 2 parallel co-axial circular coil = R
            Number of turns = N
            Current in both coils = I
            Distance between the 2 coils = 2R
           
            As the point where we have to find the magnetic field is half way between the 2 coils, it will be at a distance of R from center of both the coils.
 
So the magnetic field at the point because of coil 1 = B1
 
So, B1 = (μoNIR2) / 2[(R+R)2+R]3/2
 
Similarly, B2 = (μoNIR2) / 2[(R+R)2+R]3/2
           
            So, the total magnetic field, B = B1 + B2
           
  • B = B1 + B2
  = (μoNIR2) / 2[(R+R)2+R]3/2  + (μoNIR2) / 2[(R+R)2+R]3/2
                   = (μoNIR2) / [(R+R)2+R]3/2
                        = (μoNIR2) / [4R2+R] 3/2
                        = (μoNIR2) /8R3[1+1/R]3/2
                        Since, R>>1 we can say
B = (μoNIR2) /8R3
 

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the solution to your problem.
 
Radius of 2 parallel co-axial circular coil = R
Number of turns = N
Current in both coils = I
Distance between the 2 coils = 2R     
As the point where we have to find the magnetic field is half way between the 2 coils, it will be at a distance of R from center of both the coils.
So the magnetic field at the point because of coil 1 = B1
So, B1 = (μoNIR2) / 2[(R+R)2+R]3/2
Similarly, B2 = (μoNIR2) / 2[(R+R)2+R]3/2
So, the total magnetic field, B = B1 + B2
B = B1 + B2  = (μoNIR2) / 2[(R+R)2+R]3/2  + (μoNIR2) / 2[(R+R)2+R]3/2
                    = (μoNIR2) / [(R+R)2+R]3/2
                    = (μoNIR2) / [4R2+R] 3/2
                    = (μoNIR2) /8R3[1+1/R]3/2
Since, R>>1 we can say
B = (μoNIR2) /8R3
 
Thanks and regrads,
Kushagra

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Other Related Questions on magnetism

question mark
Four long co-axial thin walled cylindrical conductor A, B, C and D have radii R. 2R 3R and 4R respectively. A and C carry current I and 31 respectively to plane of paper on the other hand, B and D carry and 41 respectively outward to plane of paper. Then 21
magnetism
0 Answer Available

Last Activity: 2 Years ago

question mark
I need solution of these questions.............................Magnetic effect of current
magnetism
0 Answer Available

Last Activity: 3 Years ago

question mark
A freely suspended iron rod does not point at N-S directions alwalys .why
 
 
magnetism
0 Answer Available

Last Activity: 3 Years ago

question mark
What is magnetic entropy change? For my knowledge, I know entropy is randomness or disorder. So here that magnetic refers to the magnetic dipole moments?
magnetism
1 Answer Available

Last Activity: 3 Years ago

question mark
Derive the relation between magnetic field intensity (H) and magnetization (M) for a magnetic material placed in a magnetizing field. 
magnetism
0 Answer Available

Last Activity: 3 Years ago