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there exists a uniform cylindrcally symmetric magnetic field directed along the axis of a cylinder but varying with time as B = kt.
if an electron is released from rest in this field at a distance r from the axis of cylinder, its acceleration ,just after it is released would be what





given e and m are electronic charge and mass respectively

Radhika Batra , 12 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To determine the acceleration of an electron released from rest in a time-varying magnetic field, we need to apply some fundamental concepts from electromagnetism, particularly those related to the Lorentz force. The magnetic field in this scenario is given as B = kt, where k is a constant and t is time. This means that the magnetic field strength increases linearly with time.

Understanding the Lorentz Force

The force experienced by a charged particle moving in a magnetic field is described by the Lorentz force equation:

F = q(v × B)

Where:

  • F is the magnetic force on the particle.
  • q is the charge of the particle (for an electron, this is approximately -1.6 x 10-19 C).
  • v is the velocity of the particle.
  • B is the magnetic field vector.

Initial Conditions

When the electron is released from rest, its initial velocity v is zero. Therefore, at the moment of release, the cross product of velocity and magnetic field will also be zero:

F = q(0 × B) = 0

This means that initially, there is no magnetic force acting on the electron, and thus no acceleration.

Induced Electric Field

However, we must consider that a time-varying magnetic field can induce an electric field according to Faraday's law of electromagnetic induction. The induced electric field E in a region where the magnetic field is changing can be expressed as:

E = -dB/dt

Given that B = kt, we can differentiate this with respect to time:

dB/dt = k

Thus, the induced electric field is:

E = -k

Force on the Electron

The force acting on the electron due to this induced electric field can be calculated using:

F = qE

Substituting the values, we get:

F = q(-k)

Since the charge of the electron is negative, the force will be positive in the direction of the electric field:

F = -(-1.6 x 10-19 C)(k) = 1.6 x 10-19 k

Calculating Acceleration

Now, we can find the acceleration a of the electron using Newton's second law:

F = ma

Rearranging gives:

a = F/m

Substituting the force we calculated:

a = (1.6 x 10-19 k) / m

Where m is the mass of the electron, approximately 9.11 x 10-31 kg. Therefore, the acceleration of the electron just after it is released is:

a = (1.6 x 10-19 k) / (9.11 x 10-31)

Final Thoughts

In summary, while the magnetic force is zero at the moment of release due to the electron's initial rest state, the changing magnetic field induces an electric field that exerts a force on the electron. This results in an acceleration that can be calculated using the charge and mass of the electron. The key takeaway is that even in a magnetic field, the dynamics of charged particles can be significantly influenced by induced electric fields.

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