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Grade 12th passMagnetism

Q. A wire of mass 100gm, length 1m and current 5 ampere is balanced in mid air by a magnetic field B, then find the value of B.

Profile image of Naina Singh
9 Years agoGrade 12th pass
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2 Answers

Profile image of Khimraj
9 Years ago
ILB = mg5*1*B =(1/10)10B =1/5 T. Hope it clears. If u have doubt then please ask.Please approve the answer.
Profile image of Shreya D Nanda
9 Years ago
Hi,
As the wire is balanced in mid air, the downward force is equal to the upward force, i.e, the gravitational force is equal to the magnetic force due to the magnetic field B.
Mg=BIL \sin \theta
as B is perpendicular to the current carrying wire, \theta = 90 \Rightarrow sin\theta =1
\therefore Mg= BIL
sustituting the values, in SI units, { g = 9.8m/s2 }
0.1 * 9.8 = B * 5 * 1
B= 0.98/5 T
or B= 0.196 T.
 
hope it is understandable,...