Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Q. A wire of mass 100gm, length 1m and current 5 ampere is balanced in mid air by a magnetic field B, then find the value of B.

Q.  A wire of mass 100gm, length 1m and current 5 ampere is balanced in mid air by a magnetic field B, then find the value of B.

Grade:12th pass

2 Answers

Khimraj
3007 Points
4 years ago
ILB = mg5*1*B =(1/10)10B =1/5 T. Hope it clears. If u have doubt then please ask.Please approve the answer.
Shreya D Nanda
74 Points
4 years ago
Hi,
As the wire is balanced in mid air, the downward force is equal to the upward force, i.e, the gravitational force is equal to the magnetic force due to the magnetic field B.
Mg=BIL \sin \theta
as B is perpendicular to the current carrying wire, \theta = 90 \Rightarrow sin\theta =1
\therefore Mg= BIL
sustituting the values, in SI units, { g = 9.8m/s2 }
0.1 * 9.8 = B * 5 * 1
B= 0.98/5 T
or B= 0.196 T.
 
hope it is understandable,...
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free