Hi. I have three questionns to ask.A very close point on the axis foo a current carrying circular coil (x(a) R/10^1/2(b) R/30^1/2(C) R/50^1/2(d) R/150^1/2 2. A charge +2q moves vertically upwards with speed v, a second charge -q moves horizontally to the right with the same speed v, and a third charge +q moves horizontal to the right with the same speed v. The point P is located a perpendicular distance a away from each charge as shown in the figure. The magnetic field at P is .. Here’s the diagram:-q ----------> v||^ v||||. P ----------o +2q||| o---------> v (+q) Answer is :Out of the page with magnitude u(naught) 4qv/4pia^2The equation of line on which magnetic field is zero due to system of two perpendicular infinitely long current carryng straight wire is :-^ +Y axis|| (current flowing thru here is 3I)||---------------------------------------------------------> x|(current flowing in +x is I)||The answer is x=3y

Ethan Moises , 7 Years ago

Grade 12