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A steady current flow in a long wire.it is bent into a circular loop of one turn and magnetic field at centre is B.if same wire is bent into a circular loop of n turns magnetic field at the centre of the coil is
Hii Magnetic field at the centre of circle of radius a is B = mew *I/2aIf no, of turns increased Radius r = a/N No, of loops has also increased to N so, magnetic field at centre will be Bnew = mew * N*I/2r = mew * N2I/2a => N2B
Here length of the wire is considered fixed. So the radius of the small turns r=R/N; where R the radius of the big circular loop.then B=Mu_0* I/(2*pi*R)and for the later case mag. field =Mu_0*I/(2*pi*(R/N))=BN.Edit1: But the current also increases N times so the ans is BN^2.
Here length of the wire is considered fixed. So the radius of the small turns r=R/N; where R the radius of the big circular loop.
then B=Mu_0* I/(2*pi*R)
and for the later case mag. field =Mu_0*I/(2*pi*(R/N))
=BN.
Edit1: But the current also increases N times so the ans is BN^2.
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