Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A steady current flow in a long wire.it is bent into a circular loop of one turn and magnetic field at centre is B.if same wire is bent into a circular loop of n turns magnetic field at the centre of the coil is
Hii Magnetic field at the centre of circle of radius a is B = mew *I/2aIf no, of turns increased Radius r = a/N No, of loops has also increased to N so, magnetic field at centre will be Bnew = mew * N*I/2r = mew * N2I/2a => N2B
Here length of the wire is considered fixed. So the radius of the small turns r=R/N; where R the radius of the big circular loop.then B=Mu_0* I/(2*pi*R)and for the later case mag. field =Mu_0*I/(2*pi*(R/N))=BN.Edit1: But the current also increases N times so the ans is BN^2.
Here length of the wire is considered fixed. So the radius of the small turns r=R/N; where R the radius of the big circular loop.
then B=Mu_0* I/(2*pi*R)
and for the later case mag. field =Mu_0*I/(2*pi*(R/N))
=BN.
Edit1: But the current also increases N times so the ans is BN^2.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -