A long rigid wire lies along X-axis and carries a current of 10 Amp in a positive X-direction. Round the wire external magnetic field B=i+3x^2j with x in meter and B in tesla. The segment of the wire between x=1 and x=4 is?

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Geeta Singh · Answer

∫dF = ∫i(dl×B) dl=dx i ^ B= i ^ + 2x^2 j ^ ii= 10A integerating x=1 to x=4, 10(2x^2 dx) =((20x^3)/3)1 to 4 we get F=420( D) Thankyouu!

Khimraj · Answer

The magnetic force (in SI units) on the segment of the wire between x = 1 m and x = 4 m is given by 10(2x^2 dx) =((20x 3 )/3)1 to 4 F=420

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A long rigid wire lies along X-axis and carries a current of 10 Amp in a positive X-direction. Round the wire external magnetic field B=i+3x^2j with x in meter and B in tesla. The segment of the wire between x=1 and x=4 is?

A long rigid wire lies along X-axis and carries a current of 10 Amp in a positive X-direction. Round the wire external magnetic field B=i+3x^2j with x in meter and B in tesla. The segment of the wire between x=1 and x=4 is?

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