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        A long rigid wire lies along X-axis and carries a current of 10 Amp in a positive X-direction. Round the wire external magnetic field B=i+3x^2j with x in meter and B in tesla. The segment of the wire between x=1 and x=4 is?
7 months ago

Geeta Singh
5 Points
							∫dF = ∫i(dl×B)dl=dx i^ B= i^ + 2x^2 j^ii= 10Aintegerating x=1 to x=4,$\int_{1}^{4}$10(2x^2 dx) =((20x^3)/3)1 to 4we get F=420( D) Thankyouu!

6 months ago
Khimraj
3008 Points
							The magnetic force (in SI units) on the segment of the wire between x = 1 m and x = 4 m is given by $\int_{1}^{4}$10(2x^2 dx) =((20x3)/3)1 to 4 F=420

5 months ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions