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A long rigid wire lies along X-axis and carries a current of 10 Amp in a positive X-direction. Round the wire external magnetic field B=i+3x^2j with x in meter and B in tesla. The segment of the wire between x=1 and x=4 is?

Himanshu Gupta , 6 Years ago
Grade 12th pass
anser 2 Answers
Geeta Singh

Last Activity: 5 Years ago

∫dF = ∫i(dl×B)
dl=dx i^ 
B= i^ + 2x^2 j^
ii= 10A
integerating x=1 to x=4,
\int_{1}^{4}10(2x^2 dx)
 
=((20x^3)/3)1 to 4
we get F=420( D)
 
Thankyouu!
 

Khimraj

Last Activity: 5 Years ago

The magnetic force (in SI units) on the segment of the wire between x = 1 m and x = 4 m is given by
 
\int_{1}^{4}10(2x^2 dx)
 
=((20x3)/3)1 to 4
 F=420
 

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