a charge is uniformly distributed on a circular ring of radius r now the ring is rotated with angular velocity w about the diameter of the ring. calculate the magnetic moment of the circular ring

Question

Vikas TU · Answer

Hiii I am calculating the magnetic moment of the circular ring at the centre of the ring. The total magnetic induction at the centre of the ring will be mew* q*w/4*pie*r I = q/t I = q*w/2*pie Magnetic field at the centre of current carrying conductor = mew*I / 2*r Putting the value of I we ger B = mew* q*w/4*pie*r

Khimraj · Answer

The total magnetic induction at the center of the ring will be μ₀qω/4πr Explanation: since the total charge is q and we know that current = charge/time => I = q/t The angular velocity is equal to ω = 2π/t Time period, t = 2π/ω => I = qω/2π we know that magnetic field at the center of a current carrying conductor, B = μ₀I/2r putting the value of I from the above equation, we get B = (μ₀/2r) x qω/2π => B = μ₀qω/4πr Hence the total magnetic induction at the center of the ring will be μ₀qω/4πr

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a charge is uniformly distributed on a circular ring of radius r now the ring is rotated with angular velocity w about the diameter of the ring. calculate the magnetic moment of the circular ring

a charge is uniformly distributed on a circular ring of radius r now the ring is rotated with angular velocity w about the diameter of the ring. calculate the magnetic moment of the circular ring

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