A beam of protons with a velocity 4 x 10 5 m / sec enters a uniform magnetic field of 0.3 tesla at an angle of 60° to the magnetic field. Also find the pitch of the helix (which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation )

Question

Navjyot Kalra · Answer

Hello Student,

Please find the answer to your question

v₁ is responsible for horizontal motion of proton

v₂ is responsible for circular motion of proton

∴ mv²₂ / r = qv₂ B

r = mv² /qB = 1. 76 x 10^-27 x 4 x 10⁵ x √3 / 1. 6 x 10^-19 x 0.3 x 2 = 0.012 m

Pitch of helix = v₁ x T

Where T = 2πr / v₂ = 2πr / v sin θ

⇒ Pitch of helix = v cos θ x 2πr / v sin θ

= 2 πr cosθ = 2x 3.14 x 0.012 x cot 60° = 0.044 m

Thanks
Navjot Kalra
askIITians Faculty

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

A beam of protons with a velocity 4 x 10 5 m / sec enters a uniform magnetic field of 0.3 tesla at an angle of 60° to the magnetic field. Also find the pitch of the helix (which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation )

A beam of protons with a velocity 4 x 10⁵ m / sec enters a uniform magnetic field of 0.3 tesla at an angle of 60° to the magnetic field. Also find the pitch of the helix (which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation )

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Magnetism

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

A beam of protons with a velocity 4 x 10 5 m / sec enters a uniform magnetic field of 0.3 tesla at an angle of 60° to the magnetic field. Also find the pitch of the helix (which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation )

A beam of protons with a velocity 4 x 105 m / sec enters a uniform magnetic field of 0.3 tesla at an angle of 60° to the magnetic field. Also find the pitch of the helix (which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation )

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Magnetism

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

A beam of protons with a velocity 4 x 10⁵ m / sec enters a uniform magnetic field of 0.3 tesla at an angle of 60° to the magnetic field. Also find the pitch of the helix (which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation )