We have to find the integral of 3x⁴-1/(x⁴+x+1)² options are 1) x/(x⁴+x+1) 2) -x/(x⁴+x+1) 3) x+1/(x⁴+x+1) 4) -x-1/(x⁴+x+1)

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Aditya Gupta · Answer

Divide the numerator and denominator by x^2. We get (3x^2-1/x^2)/(x^3+1+1/x)^2 Now put x^3+1+1/x= y So integral becomes dy/y^2 So final answer is -x/(x^4+x+1)+C

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We have to find the integral of 3x⁴-1/(x⁴+x+1)² options are 1) x/(x⁴+x+1) 2) -x/(x⁴+x+1) 3) x+1/(x⁴+x+1) 4) -x-1/(x⁴+x+1)

We have to find the integral of 3x⁴-1/(x⁴+x+1)² options are
1) x/(x⁴+x+1)
2) -x/(x⁴+x+1)
3) x+1/(x⁴+x+1)
4) -x-1/(x⁴+x+1)

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We have to find the integral of 3x⁴-1/(x⁴+x+1)² options are 1) x/(x⁴+x+1) 2) -x/(x⁴+x+1) 3) x+1/(x⁴+x+1) 4) -x-1/(x⁴+x+1)

We have to find the integral of 3x⁴-1/(x⁴+x+1)² options are 1) x/(x⁴+x+1)2) -x/(x⁴+x+1)3) x+1/(x⁴+x+1)4) -x-1/(x⁴+x+1)

1 Answers

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We have to find the integral of 3x⁴-1/(x⁴+x+1)² options are
1) x/(x⁴+x+1)
2) -x/(x⁴+x+1)
3) x+1/(x⁴+x+1)
4) -x-1/(x⁴+x+1)