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∫tanx)^1/2dx/(1+(tanx)^1/2) limit is from 0 to pi/2

∫tanx)^1/2dx/(1+(tanx)^1/2) limit is from 0 to pi/2

Grade:12

1 Answers

Aditya Gupta
2080 Points
2 years ago
Let I be the required integral.
Now replace the function f(x) inside by f(a+b-x)
It becomes 1/(1+tanx^.5)dx
Now adding, you get 
2I= ∫1dx
2I= pi/2
Or I=π/4

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