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∫tanx)^1/2dx/(1+(tanx)^1/2) limit is from 0 to pi/2
Let I be the required integral.Now replace the function f(x) inside by f(a+b-x)It becomes 1/(1+tanx^.5)dxNow adding, you get 2I= ∫1dx2I= pi/2Or I=π/4
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