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Solve the following integral. ..............................................

Ashok Eswar , 7 Years ago
Grade 12
anser 1 Answers
venkat
In these kind of sums the first thing you have to do is to put x=t2
then tx=2tdt
substitute it in the integral you will get
\int \sqrt{(1-t)/(1+t)} \ 2tdt
Now rationalise the denominator with 1-t
2\int t-t^2/\sqrt{(1-t^2)} \ dt 
now split the integral into two parts
\int 2tdt/\sqrt{(1-t^2)} \ -2\int{t^{2}dt/\sqrt{1-t^{2}}}
We know that integral of f ‘(x)/sqrt f(x) =2f(x)^1/2 and adding ,subtracting 1 in the second part of the integral we get
2\sqrt{(1-t^2)} \ +2\int{(1-t^{2}+1)dt/\sqrt{1-t^{2}}}
2\sqrt{(1-t^2)} \ +2\int\sqrt{(1-t^{2})}dt-2\int dt/\sqrt{1-t^{2}}
Then by using the identites we get that
2\sqrt{(1-t^2)} + \sqrt{1-t^{2}}-sin^{-1}\sqrt{1-t^{2}}
now replacing t2 with x we get
2\sqrt{(1-x)} + \sqrt{1-x}-sin^{-1}\sqrt{1-x}+c
and that is your answer
Please approve my answer if it helped you.
Last Activity: 7 Years ago
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