badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 10

                        

Please solve this question. Ans : Option 1 .............

one year ago

Answers : (1)

Aditya Gupta
2065 Points
							
hello myra, this problem s superbly easy once you draw the graph. you ll note that both curves intersect at 3 points viz. x= 0, pi/2, pi. also, the area bounded b/w the curves from x=0 to pi/2 is equal to area bounded b/w the curves from x=pi/2 to pi (by simple symmetry or you can prove by integration).
so total area would bounded would be twice the are bounded b/w 0 to pi/2, which is equal to
∫ from 0 to pi/2 (cosx)dx – area of triangle formed by axes and line y= 1 – 2x/pi
= 1 – ½ *1*(pi/2)
= 1 – pi/4.
so, double this area= 2 – pi/2
kindly approve :)
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details