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please help anyone............jitendra sir where are you please help ….....

milind , 11 Years ago
Grade 12
anser 2 Answers
Jitender Singh
Ans:
Hello Student,
Please find answer to your question below

log_{sinx}tanx >= 0
sinx should be b/w 0 & 1 (with both excluded)
\Rightarrow 0<x<\frac{\pi }{2}
log_{sinx}tanx >= log_{sinx}1
Since base(sinx) is less than 1. So when we cancel it out, inequality sign will change
tanx =< 1
\Rightarrow 0 =< x =< \frac{\pi }{4}
Intesection of both solution is
0 < x =< \frac{\pi }{4}

Last Activity: 11 Years ago
milind
jitendra sir in third step .inequality sign changes why ? /............ thanks for your help ….…....
 
Last Activity: 11 Years ago
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