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Grade 12Integral Calculus

please help anyone............jitendra sir where are you please help ….....

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milind

11 Years agoGrade 12

2 Answers

Jitender Singh

11 Years ago

Ans:
Hello Student,
Please find answer to your question below

$log_{sinx}tanx >= 0$
sinx should be b/w 0 & 1 (with both excluded)
$\Rightarrow 0<x<\frac{\pi }{2}$
$log_{sinx}tanx >= log_{sinx}1$
Since base(sinx) is less than 1. So when we cancel it out, inequality sign will change
$tanx =< 1$
$\Rightarrow 0 =< x =< \frac{\pi }{4}$
Intesection of both solution is
$0 < x =< \frac{\pi }{4}$

milind

11 Years ago

jitendra sir in third step .inequality sign changes why ? /............ thanks for your help ….…....

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