Grade 12th passIntegral Calculus
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1 Answer
Nandana
hi … !
e(t) -e(0) = ∫Vm sin(wt)Im sin(wt-G) dt = Vm Im ∫t sin(wt){sinwt.cosG -sinG.coswt} dt
= Vm Im cosG [ ∫t(1-cos(2wt))/2 dt – sinG /w sin(wt)]
= Vm Im [0.5cosG -0.25/w sin(2wt) – sinG /w sin(wt)]
( where ‘w’ =3.14 )
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