integrate with respect to x : ∫1/(a 2 – 4x 2 ) 1/2 dx (a) ½ sin -1 (2x/a) +c (b)1/a sin -1 (2x/a) +c (c)2/3 sin -1 (2x/a) +c (d)2 / 3 1/2 sin -1 (2x/a) +c

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Arun · Answer

Dear student It is standard bfirmula Its answer will be (1/2) sin -1 (2x/a) + constant Hence option A is correct

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integrate with respect to x : ∫1/(a 2 – 4x 2 ) 1/2 dx (a) ½ sin -1 (2x/a) +c (b)1/a sin -1 (2x/a) +c (c)2/3 sin -1 (2x/a) +c (d)2 / 3 1/2 sin -1 (2x/a) +c

integrate with respect to x : ∫1/(a² – 4x²)^1/2 dx

(a) ½ sin^-1(2x/a) +c
(b)1/a sin^-1(2x/a) +c
(c)2/3 sin^-1(2x/a) +c
(d)2 / 3^1/2 sin^-1(2x/a) +c

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integrate with respect to x : ∫1/(a 2 – 4x 2 ) 1/2 dx (a) ½ sin -1 (2x/a) +c (b)1/a sin -1 (2x/a) +c (c)2/3 sin -1 (2x/a) +c (d)2 / 3 1/2 sin -1 (2x/a) +c

integrate with respect to x : ∫1/(a2 – 4x2)1/2 dx (a) ½ sin-1(2x/a) +c(b)1/a sin-1(2x/a) +c(c)2/3 sin-1(2x/a) +c(d)2 / 31/2 sin-1(2x/a) +c

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integrate with respect to x : ∫1/(a² – 4x²)^1/2 dx

(a) ½ sin^-1(2x/a) +c
(b)1/a sin^-1(2x/a) +c
(c)2/3 sin^-1(2x/a) +c
(d)2 / 3^1/2 sin^-1(2x/a) +c