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anti derivative of 1/sin2x cos2x

bikash , 11 Years ago
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anser 1 Answers
Yash Jain
We have, I = ∫ dx/Sin2xCos2x
On multiplying and dividing by the factor of 4 we get,
I = 4 ∫ dx/Sin22x = 4 ∫ Cosec22xdx
Therefore, I = 4*(-Cot2x)/2 + C = -2Cot2x + C

 
Last Activity: 11 Years ago
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