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Please check my answer and tell me where I am wrong? The answer according to the answer key for thi question is 2
0∫pi/2(1+sin x)1/2dx = 0∫pi/2(sin x/2 + cos x/2)dx = [-2cos x/2 + 2sin x/2]0pi/2 = -2cos pi/4 + 2sin pi/4 = -√2 + √2 = 0
you have not substituted the lower limit
its right upto the step of subs the limits
ie -2cospi/4+ 2sin pi/4 -(-2 cos 0 + 2sin0)
= 0 - (-2) = 2
remember cos 0 is 1
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