Area under the curves

Question

The area bounded by the straight lines x=0 , x=2 and the curve y =2 x , y= 2x-x2 is (a)4/3 -1/log2 (b) 3/log2 + 4/3 (c)4/ log2 -1 (d) 3/ log2 - 4/3

Ramesh V · Accepted Answer

coloured area to be found out Area = int (2x) frm (0,2) - int (2x -x2) frm (0,2) = [2x/log2 - x2 + x3/3] = (9 - 4 log2)/log8 -- Ramesh

The area bounded by the straight lines x=0 , x=2 and the curve y =2 ^x , y= 2x-x² is

(a)4/3 -1/log2 (b) 3/log2 + 4/3 (c)4/ log2 -1

(d) 3/ log2 - 4/3