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The area bounded by the straight lines x=0 , x=2 and the curve y =2 x , y= 2x-x2 is
(a)4/3 -1/log2 (b) 3/log2 + 4/3 (c)4/ log2 -1
(d) 3/ log2 - 4/3
coloured area to be found out
Area = int (2x) frm (0,2) - int (2x -x2) frm (0,2)
= [2x/log2 - x2 + x3/3]
= (9 - 4 log2)/log8
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Ramesh
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