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∫x5dx/√(1-x2)
Hi Suhas,
Substitute 1-x^2 = t^2, so that xdx = -tdt
And x^4 = (1-t^2)^2.
Integral will be ∫(1-t^2)^2dt.
This is directly integrable, once you expand it.
Hope it helps.
Best Regards,
Ashwin (IIT MadraS).
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