∫x5dx/√(1-x2)
Last Activity: 13 Years ago
Hi Suhas,
Substitute 1-x^2 = t^2, so that xdx = -tdt
And x^4 = (1-t^2)^2.
Integral will be ∫(1-t^2)^2dt.
This is directly integrable, once you expand it.
Hope it helps.
Best Regards,
Ashwin (IIT MadraS).
1-x^2/x^5 = -x^3 -x + x/1-x^2 then easily interegrate all these so ans - -X^4/4-X^2/2 + LOG(1-X^2)/2 = CONST.
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Last Activity: 2 Years ago
Last Activity: 3 Years ago