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The value of ∫x2(1-x)3/2dx
Hi Suhas,
Make the sub 1-x = t^2, so that dx = -2tdt.
And the integral becomes ∫[(1-t^2)^2](t^3)[-2tdt].
Open the brackets, and you will get a directly integrable function.
Hope it helps.
Best Regards,
Ashwin (IIT MadraS).
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