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Prove ∫ dx / (sec x + cosec x) = (1/2) (sinx-cosx) + 1/(2) 1/2 log | (tan x/2 - 1 - root2) / (tanx -1 + root2)|

Prove


∫ dx / (sec x + cosec x) = (1/2) (sinx-cosx) + 1/(2) 1/2   log | (tan x/2 - 1 - root2) / (tanx -1 + root2)|

Grade:12

1 Answers

Sumit Majumdar IIT Delhi
askIITians Faculty 137 Points
7 years ago
Dear student,
When we integrate:
\int \frac{dx}{secx+cosecx}
We get:
68-1874_Sol.JPG
This can be simplified to get the required result.
Regards
Sumit

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