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Prove ∫ dx / (sec x + cosec x) = (1/2) (sinx-cosx) + 1/(2) 1/2 log | (tan x/2 - 1 - root2) / (tanx -1 + root2)|
Prove
∫ dx / (sec x + cosec x) = (1/2) (sinx-cosx) + 1/(2) 1/2 log | (tan x/2 - 1 - root2) / (tanx -1 + root2)|
Dear student,When we integrate:We get:This can be simplified to get the required result.RegardsSumit
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