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Solve the integral
you can write separately as: = x/(x+1)2 - 3/(x+1)2 + 2/x.(x+1)2 = (x+1-1)/(x+1)2 - 3/(x+1)2 + 2/x.(x+1)2 = 1/(x+1) - 4/(x+1)2 + 2/x.(x+1)2 = 1/(x+1) - 4/(x+1)2 + 2/x - 2/(x+1) - 2/(x+1)2 = 2/x - 1/(x+1) - 6/(x+1)2 on integrating gives 2 lnx - ln(x+1) +6/(x+1) +C
you can write separately as:
= x/(x+1)2 - 3/(x+1)2 + 2/x.(x+1)2
= (x+1-1)/(x+1)2 - 3/(x+1)2 + 2/x.(x+1)2
= 1/(x+1) - 4/(x+1)2 + 2/x.(x+1)2
= 1/(x+1) - 4/(x+1)2 + 2/x - 2/(x+1) - 2/(x+1)2
= 2/x - 1/(x+1) - 6/(x+1)2
on integrating gives
2 lnx - ln(x+1) +6/(x+1) +C
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