integration between (-1to 3/2) of |x sin((pi)x)|=kp².find the value of k? (where | | is the modulus function)

For x:   -1<x<0        |x sin((pi)x)| is positive

For x:   0<x<1          |x sin((pi)x)| is positive

For x:   1<x<3/2       |x sin((pi)x)| is negative

so, its

integration from (-1 to 1)  x sin((pi)x).dx  -   integration from (1 to 3/2)  x sin((pi)x).dx

integral of x sin((pi)x).dx  is       -x.cos((pi)x)/Pi  +  sin((pi)x)/(Pi)²

so value is

1/Pi -  1/(Pi)²