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how to integrate 1/(1+x^3)^1/2
Dear student,
let (1+x^3) = t^2
=> 3x^2*dx = 2tdt
=> dx = 2tdt/3x^2
substitute this in integral euation,
∫(1+x^3)^-1/2 * 2tdt/3x^2
=> ∫ 2dt/3*(t-1)^(2/3)
put t-1 = k
=> ∫ 2*dk/3*k^(2/3)
=> 2k^1/3
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