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integrate frm 0 to x : [cost]dt where x belongs to(2npi,(4n+1)pi/2) where [.]denotes gif

integrate frm 0 to x : [cost]dt


where x belongs to(2npi,(4n+1)pi/2) where [.]denotes gif

Grade:12

1 Answers

Chetan Mandayam Nayakar
312 Points
11 years ago

[cost] =1 for 2npi≤t≤(4n+1)pi/2

therefore integral is ∫dt from 2npi to (4n+1)pi/2 = π/2

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