∫ 0 infinity x n-1 /1+x dx = π/sin nπ 0 I wnat proof of this

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Aditya Gupta · Answer

this is done using complex analysis and gamma functions, none of which is in jee syllabus. this ques can never be asked in any engineering entrance exam. you will have to learn complex analysis which is only taught in college.

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∫ 0 infinity x n-1 /1+x dx = π/sin nπ 0 I wnat proof of this

∫₀^infinityx^n-1/1+x dx = π/sin nπ 0
I wnat proof of this

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∫ 0 infinity x n-1 /1+x dx = π/sin nπ 0 I wnat proof of this

∫0infinityxn-1/1+x dx = π/sin nπ 0I wnat proof of this

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∫₀^infinityx^n-1/1+x dx = π/sin nπ 0
I wnat proof of this