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The vapour density of a gaseous mixture containing only Ar and N2O4 gases, is 40. When the mixture is left for some time, the vapour density decreased and finally becomes 37.5. It happened due to dissociation of some N2O4 AND NO2. (Ar=40) What is the initial mole ratio of Ar and N2O4?

The vapour density of a gaseous mixture containing only Ar and N2O4 gases, is 40. When the mixture is left for some time, the vapour density decreased and finally becomes 37.5. It happened due to dissociation of some N2O4 AND NO2. (Ar=40)
What is the initial mole ratio of Ar and N2O4?

Grade:11

1 Answers

Arun
25758 Points
2 years ago
Mol mass of mixture =2×38.3=76.6 
 
No. of moles in 100 g of mixture = 
76.6
100
​ 
 
 
Let a g of NO 
2
​ 
  is present in mixture. 
 
MolesofNO 
2
​ 
 +MolesofN 
2
​ 
 O 
4
​ 
 =Molesofmixture
 
46
a
​ 
 + 
92
100−a
​ 
 = 
76.6
100
​ 
  "or" a=20.10g
 
Moles of NO 
2
​ 
  in mixture = 
46
20.10
​ 
 =0.437

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