Grade 10Inorganic Chemistry
The percent of N in 66% pure (NH402 4 sample is A-32,b-28
1 Answer
somi teez
i think your compound is (nh4)2 so4
now,
molecular mass of compound=2*(14+1*4)+32+16*4
=2*18+32+64
= 36+96
=132g
atomic weight of nitrogen=28g
so,
% of nitrogen in 66% =28/(66/100 *132) %=32 % approx
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