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The percent of N in 66% pure (NH402 4 sample is A-32,b-28

kittu , 7 Years ago
Grade 10
anser 1 Answers
somi teez

Last Activity: 7 Years ago

i think your compound is (nh4)2 so4
now,
molecular mass of compound=2*(14+1*4)+32+16*4
                                           =2*18+32+64
                                          = 36+96
                                          =132g
atomic weight of nitrogen=28g
so,
  % of nitrogen in 66% =28/(66/100 *132) %=32 % approx

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